(y/y^2-3y-10)-(3/y+2)

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Solution for (y/y^2-3y-10)-(3/y+2) equation: 


D( y )

y = 0

y^2 = 0

y = 0

y = 0

y^2 = 0

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in (-oo:0) U (0:+oo)

y/(y^2)-(3*y)-(3/y)-10-2 = 0

y/(y^2)-3*y-3*y^-1-10-2 = 0

-3*y^1-2*y^-1-12*y^0 = 0

(-3*y^2-12*y^1-2*y^0)/(y^1) = 0 // * y^2

y^1*(-3*y^2-12*y^1-2*y^0) = 0

y^1

-3*y^2-12*y-2 = 0

-3*y^2-12*y-2 = 0

DELTA = (-12)^2-(-3*(-2)*4)

DELTA = 120

DELTA > 0

y = (120^(1/2)+12)/(-3*2) or y = (12-120^(1/2))/(-3*2)

y = (2*30^(1/2)+12)/(-6) or y = (12-2*30^(1/2))/(-6)

y in { (2*30^(1/2)+12)/(-6), (12-2*30^(1/2))/(-6)} 

y in { (2*30^(1/2)+12)/(-6), (12-2*30^(1/2))/(-6) }

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